
Grade 12IIT JEE Entrance Exam
A projectile is given an initial velocity of (i +2j) m/s, where i is along the ground and j is along the vertical. If g=10 m/s^2, the equation of its trajectory is: a) y= 2x – 5x^2 b) y= x – 5x^2 c) 4y= 2x – 5x^2 d) y= 2x + 5x^2
A projectile is given an initial velocity of (i +2j) m/s, where i is along the ground and j is along the vertical. If g=10 m/s^2, the equation of its trajectory is:
a) y= 2x – 5x^2
b) y= x – 5x^2
c) 4y= 2x – 5x^2
d) y= 2x + 5x^2




