A passenger and a goods train are headed n the same direction on parallel tracks. the passenger train is 240 m long and has a constant velocity of 72kmph. Initially the engine of the passenger train approaches the last wagon of the goods train, t takes 25 s to be in level with the engine of the goods train. if it took 30 s more to completely overtake the goods train, then what is the lenght of the gods train ?

Question

Shubham Sahoo · Answer

Let the length and velocity of goods train to be ‘y’ m and ’x’ m/s respectively. Now, velocity of passenger train = 72km/h = 72* 5/18 = 20 m/s. Also, given length of passenger train = 240 m. Relative velocity of passenger train with respect to goods train = (20 – x) m/s. Distance covered by passenger train with respect to goods train in 25 s is given by: y = (20 – x)* 25------(1) Also, distance covered by passenger train with respect to goods train to overtake it in 30 s is given by : 240 = (20 – x)* 30------(2) Now, dividing equation (1) by (2) on both the sides simultaneously, we get : y/240 = 25/30 On solving the above equation we got : y = 200 m Hence, the length of goods train is 200 m.

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