Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A passenger and a goods train are headed n the same direction on parallel tracks. the passenger train is 240 m long and has a constant velocity of 72kmph. Initially the engine of the passenger train approaches the last wagon of the goods train, t takes 25 s to be in level with the engine of the goods train. if it took 30 s more to completely overtake the goods train, then what is the lenght of the gods train ?

A passenger and a goods train are headed n the same direction on parallel tracks. the passenger train is 240 m long and has a constant velocity of 72kmph. Initially the engine of the passenger train approaches the last wagon of the goods train, t takes 25 s to be in level with the engine of the goods train. if it took 30 s more to completely overtake the goods train, then what is the lenght of the gods train ?

Grade:12

1 Answers

Shubham Sahoo
15 Points
3 years ago
Let the length and velocity of goods train to be ‘y’ m  and ’x’ m/s respectively.
Now, velocity of passenger train = 72km/h = 72* 5/18 = 20 m/s.
Also, given length of passenger train = 240 m.
Relative velocity of passenger train with respect to goods train = (20 – x) m/s.
Distance covered by passenger train with respect to goods train in 25 s is given by:
y = (20 – x)* 25------(1)
Also, distance covered by passenger train with respect to goods train to overtake it in 30 s is given by :
240 = (20 – x)* 30------(2)
Now, dividing equation (1) by (2) on both the sides simultaneously, we get :
y/240 = 25/30
On solving the above equation we got :
y = 200 m
Hence, the length of goods train is 200 m.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free