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A particle of mass m projected vertically with a speed u. If air resistance is R then find out time of ascent, time of descent,height and the speed with which it will return to the point of projection?
For ascentNet acceleration=g+R. (g is downwards and air resistance will oppose the motion)Now, using v=u+att=u/(g+R) Height. H=u²/2(g+R)For descentNet acceleration will be (g-R) {g will be downwards and R will be upwards)Now using h=ut +1/2at²u²/2(g+R)=1/2(g-R)t²t=u/(g²-R²)½HenceTime of ascent =u/(g+R) Time of descent =u/(g²-R²)½Height=u²/2(g+R)
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