Grade 11Mechanics

A particle moves along the parabolic path 2
y ax  in such a way that the x – component of
the velocity remains constant, say c. The acceleration of the particle is:

karan

6 Years agoGrade 11

2 Answers

Arun

6 Years ago

y =ax^2

velocity is given by:dy/dt = 2axdx/dt as x component of the velocity remains constant i.e. dx/dt = c

Vy = (2ac)x

Acceleration is given by:dVy/dt = 2acdx/dt

ay = 2ac2y =ax2velocity is given by:dydt = 2ax dx/dt

as x component of the velocity remains constant i.e.

dxdt = cVy = (2ac)xAcceleration is given by:dVy/dt = 2acdx/dtay = 2ac2

Acceleration has only y component, so acceleration of the particle is in y direction

i.e.

a→ = 2ac2 j⌢

Vikas TU

6 Years ago

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A particle moves along the parabolic path 2y ax  in such a way that the x – component of the velocity remains constant, say c. The acceleration of the particle is:

karan

2 Answers

Arun

Vikas TU

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