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Grade: 11

                        

a particle is projected vertically upward from a pont A on the ground . It takes t 1 time to reavh a point B but it still continues to mov up . If it takes further t 2 time to reach the ground from point B then the height of point B from the Ground is 1/2g (t 1 +t 2 ) 2 gt 1 t 2 1/8g(t 1 +t 2 ) 2 1/2gt 1+ t 2

one year ago

Answers : (2)

Arun
25160 Points
							
Time taken for the particle to reach highest point is t1+t22t1+t22
(v=u−gt)(v=u−gt)
Therefore initial velocity=u=g(t1+t2/2)=u=g(t1+t2/2)
Therefore heigh of B from ground is
h=ut+1/2h=ut+1/2at2at2
h=ut1−1/2h=ut1−1/2gt12gt12
=g(t1+t2/2)=g(t1+t2/2)t1−12t1−1/2gt21gt12
h=1/2h=1/2gt1t2
one year ago
Vikas TU
13786 Points
							
Dear student 
Kindly provide the image of question , 
Beciuse solution is not matching with the ans. 
We will help you 
Good Luck 
one year ago
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