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Grade: 12th pass

                        

A particle is moving in x-y plane at 2m/s along the x-axis, 2 seconds later, it’s velocity is 4m/s in a direction making 60 o with the positive x-axis. It’s average accelaration for this period of motion is: (a) root 5 m/s 2 , along y-axis (b) root 3 m/s 2 , along y-axis (c) root 5 m/s 2 , along at 60 o with the positive x-axis (d) 3 m/s 2 , at 60 o with the positive x-axis

4 years ago

Answers : (1)

RANJEET KUMAR
32 Points
							
To solve this question we need the basic understanding of rectangular coordinate axes and how to break a vector into its rectangular components.
lets take +ve x axis to be \widehat{i} and +ve ‘y’ axis to be \widehat{j} .
so initial velocity of the particle  = 2m/s \widehat{i}, and final velocity of particle after breaking it into its coordinates =  2\widehat{i} + 2\sqrt[\sqrt[]{3}\widehat{j} in m/s.
so average acceleration = [final velocity – initial velocity]/total time taken
                                       =[[2\widehat{i} + 2\sqrt[\sqrt[]{3}\widehat{j}] – 2\widehat{i}] / 2
                                       =\sqrt[\sqrt[]{3}\widehat{j} m/s2
hence the correct answer will be option [b]
thanku very much!
 
4 years ago
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