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A particle is moving in x-y plane at 2m/s along the x-axis, 2 seconds later, it’s velocity is 4m/s in a direction making 60 o with the positive x-axis. It’s average accelaration for this period of motion is: (a) root 5 m/s 2 , along y-axis (b) root 3 m/s 2 , along y-axis (c) root 5 m/s 2 , along at 60 o with the positive x-axis (d) 3 m/s 2 , at 60 o with the positive x-axis
To solve this question we need the basic understanding of rectangular coordinate axes and how to break a vector into its rectangular components.lets take +ve x axis to be and +ve ‘y’ axis to be .so initial velocity of the particle = 2m/s , and final velocity of particle after breaking it into its coordinates = 2 + 2 in m/s.so average acceleration = [final velocity – initial velocity]/total time taken =[[2 + 2] – 2] / 2 = m/s2hence the correct answer will be option [b]thanku very much!
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