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A particle is attached to one end of string the other end of which is fixed. The particle moves in vertical plane. The velocity at the lowest point is such that the particle can just complete the circle. The ratio of tension in string at A&B is


one year ago

Md Mushahid
21 Points
							when an object of mass m which is fixed to an end of an inextensible and light rodand revolving around a circular path about the other end,weight of the object and tension in the rod are getting adjusted to provide centripetal force as shown in figure, Let us consider when the object is at B, as shown in figure.Centripetal force $\frac{m\times v^{2}}{I} =T - mg\cos \theta$where T is tension in the rod, m is mass of object and θ is the angular dispalcementwhen the vertical position is taken as reference. When the object is at A, θ = 0. hence centripetal force $\frac{m\times v^{2}}{I} =T - mg$-------------2When the object is at the top most position C, θ = π, hence centripetal force $\frac{m\times v^{2}}{I} =T + mg$............(3) When the object is at top most position C, minimum required velocity vmin is obtained,by considering tension in the rod T is zero.when we apply this condition in eqn.(3), we get vmin = $\sqrt{gl}$

one year ago
Vikas TU
13786 Points
							The Expression for Velocity of Body Moving in a Vertical Circle: Consider a small body of mass 'm' attached to one end of a string and whirled in a vertical circle of radius 'r'. In this case, the acceleration of the body increases as it goes down the vertical circle and decreases when goes up the vertical circle.The ratio of tension would be = 2mg/8mg = 0.25

one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions