+91-87964 74404
FlagBACK
Question icon
Grade 12IIT JEE Entrance Exam

A metre long tube open at one end, with a moveable piston at the other end, shows resonance with a fixed frequency source (a tunning fork of frquency 340 Hz) when the tube length is 25.5 cm or 79.3 cm. Find the speed of sound in air at the temperature of the experiment. (Ignore end correction)

Profile image of durgesh shukla
9 Years agoGrade 12
Answers icon

1 Answer

Profile image of Vikas TU
6 Years ago
when successive resonance frequencies are given we consider the twice of the length difference at which these occur to be the wavelength of the waves .
Here, length of first resonance occurs ( L1) = 25.5 cm =
Length of 2nd resonance occurs ( L2) = 79.3 cm
So, wavelength = 2 × ( L2 - L1)
= 2 × ( 79.3 - 25.5)
= 2 × 53.8
= 107.6 cm
= 1.076 m
Now, speed of sound = frequency × wavelength
= 340 × 1.076 m/s
= 365.84 m/s

Other Related Questions on iit jee entrance exam

question mark

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

iit jee entrance exam
1 Answer Available

Last Activity: 10 Months ago

question mark
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
 
iit jee entrance exam
1 Answer Available

Last Activity: 3 Years ago

question mark
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago

question mark
Can class 9th students study syllabus class  of 11th 
iit jee entrance exam
3 Answers Available

Last Activity: 4 Years ago

question mark
Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago