A cubical block of side 30 cm is moving with velocity 2 m/s on a smooth surface . The surface has a bump. The angular velocity of block immediately after it hits the bump is?

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Arun · Answer

Dear Mohan Using conservation of angular momentum m*v* (0.3/2) = (2/3)* m*(0.3)&sup2;*w w = (3*2)/(4*0.3) w = 5 rad/sec Regards Arun (askIITians forum expert)

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A cubical block of side 30 cm is moving with velocity 2 m/s on a smooth surface . The surface has a bump. The angular velocity of block immediately after it hits the bump is?

A cubical block of side 30 cm is moving with velocity 2 m/s on a smooth surface . The surface has a bump. The angular velocity of block immediately after it hits the bump is?

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A cubical block of side 30 cm is moving with velocity 2 m/s on a smooth surface . The surface has a bump. The angular velocity of block immediately after it hits the bump is?

A cubical block of side 30 cm is moving with velocity 2 m/s on a smooth surface . The surface has a bump. The angular velocity of block immediately after it hits the bump is?

1 Answers

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