badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A copper wire (Y=1*10^11N/m2) of length 6m and a steel wire (2*10^11N/m2) of length 4m each of cross section 10^-5m2 are fastened end to end A load of 100N is applied to one end keeping the other end fixed the elongation produced in the copper wire is: a)0.2mm b)0.4mm c)0.6mm d)0.8mm

one year ago

Answers : (2)

Bhargav Petkar
15 Points
							
YCU=1011N/m2                                          YSTEEL=2*1011N/m2
lCu=6m                                                        lsteel=4m
therefore,change in Y=(2*1011 - 1011)  N/m2    = 1011N/m2
change in length     = 2m
hence , elongation =FL/AY=100*2/10-5*1011=0.2mm                                                      
11 months ago
Vikas TU
13783 Points
							
Dear stuent 
For more info please ollow this link 
Good Luck 
11 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details