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Grade: 11
        
A copper wire (Y=1*10^11N/m2) of length 6m and a steel wire (2*10^11N/m2) of length 4m each of cross section 10^-5m2 are fastened end to end A load of 100N is applied to one end keeping the other end fixed the elongation produced in the copper wire is:
 
  a)0.2mm   b)0.4mm  c)0.6mm  d)0.8mm
6 months ago

Answers : (2)

Bhargav Petkar
14 Points
							
YCU=1011N/m2                                          YSTEEL=2*1011N/m2
lCu=6m                                                        lsteel=4m
therefore,change in Y=(2*1011 - 1011)  N/m2    = 1011N/m2
change in length     = 2m
hence , elongation =FL/AY=100*2/10-5*1011=0.2mm                                                      
3 months ago
Vikas TU
10430 Points
							
Dear stuent 
For more info please ollow this link 
Good Luck 
3 months ago
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