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`        A composite wire consists of a steel wire of length 1.5 m and a copper wire of length 2 m , with a uniform cross section area of 2.5 * 10^-5 metre square. It is loaded with a mass of 200 kg .find the extension produced . Plzzz someone help me in solving this answer as fast as possible`
one month ago

## Answers : (1)

Arun
22607 Points
```							Given-ls = 1.5 mlc = 2 mYs = 2×10^11 N/m^2Yc = 10^11 N/m^2m = 200 kgA = 5.5×10^-5 m^2# Formula-∆l = Fl / YA∆l = mgl / YA# Solution-For steel wire,∆ls = mgls / YsAFor copper wire,∆lc = mglc / YcATotal extension is calculated by -∆l = ∆ls + ∆lc∆l = mgls/YsA + mglc/YcA∆l = (mg/A) (ls/Ys + lc/Yc)Substituting values -∆l = (200×10/5.5×10^-5) (1.5/2×10^11 + 2/10^11)∆l = (3.64×10^7) (2.75×10^-11)∆l = 0.001 m∆l = 1 mmExtension produced in the wire is 1 mm.
```
one month ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions