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Grade: 8

                        

A body of400g slides on a rough horizontal surface. If the frictional force is 3.0, the magnitude of contact force is

3 years ago

Answers : (1)

Sarfaraz Ahamed
26 Points
							
The answer is 5 newton
The contact force on the body =(N+ f)1/2
N=Normal Force on the body which is 0.4kg*10m/s2=4Newton
f=frictional force is 3 Newton (given)
therefore Contact Force is (42 + 32)1/2 = 5 Newton
2 years ago
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