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Grade: 11
        a body is projected vertically upward with an unknown velocity.if acceleration due to gravity is 10m/s2 then distance travelled by the body in last second of upward motion is?
6 months ago

Answers : (1)

Chandan
99 Points
							
Very good Question
in the last second means the ball will come to rest after one second
therefore using v+u+at
0=u-10t    (g=-10)(as opp to velocity)
as u is its initial velocity
for that second
therefore u=10m/s
use the formula for nth second distance
s(nth)=u+(a(2n-1)/2)
s=15 m
please dont forget to approve i need points urgently
 
5 months ago
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