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`        a body is projected vertically upward with an unknown velocity.if acceleration due to gravity is 10m/s2 then distance travelled by the body in last second of upward motion is?`
6 months ago

Chandan
99 Points
```							Very good Questionin the last second means the ball will come to rest after one secondtherefore using v+u+at0=u-10t    (g=-10)(as opp to velocity)as u is its initial velocityfor that secondtherefore u=10m/suse the formula for nth second distances(nth)=u+(a(2n-1)/2)s=15 mplease dont forget to approve i need points urgently
```
5 months ago
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Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions