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A body dropped from a height h with initial velocity 0, strikes the ground with a velocity 3 m/s . Another body of same mass dropped from the same height h with an initial veoocive of 4 m/s. The final velocity of second mass with which it strikes the ground
For the 1st object,u = 0v = 3m/s As the body is dropped from a height,So a = g = 10m/s2Using v2 = u2 + 2gh32 = 02 + 2(10)h9 = 20hh = 9/20mAs the second object is also dropped from the same heightSo for the second objecth = 9/20mu = 4m/sv = ?Again using v2 = u2 + 2ghv2 = 42 + 2(10)(9/20)v2 = 16 + 9v = root 25v = 5m/sThe final velocity of second object is 5m/s.
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