1800-150-456-789
FlagBACK
Flag IIT JEE Entrance Exam> A block of mass m is placed on a surface ...
question mark

A block of mass m is placed on a surface with a vertical cross section given by y = x^3/6. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is ?

Gopal Dahale , 8 Years ago
Grade 11
anser 1 Answers
Vikas TU

Last Activity: 4 Years ago

Let m be the mass of the block and μ​ be the coefficient of friction. For the sliding plane, we have
 
mgsinθ = μmgcosθ
⇒tanθ = μ
Now, we may write⇒dydx=tanθ=μ=12
We have given, y=x^3/6
∴dy/dx=x^2/2=12⇒x2=1
∴ y=16 m

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...

Other Related Questions on iit jee entrance exam

question mark
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
iit jee entrance exam
0 Answer Available

Last Activity: 2 Years ago

question mark
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
0 Answer Available

Last Activity: 2 Years ago

question mark
Can class 9th students study syllabus classof 11th
iit jee entrance exam
3 Answers Available

Last Activity: 2 Years ago

question mark
Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?
iit jee entrance exam
1 Answer Available

Last Activity: 2 Years ago

question mark
I m foreigner,How much mark i need to get into IIT??
iit jee entrance exam
1 Answer Available

Last Activity: 3 Years ago