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A block of mass 4 kg is placed on another block of mass 5kg and block B rests on a smooth horizontal surface. If the maximum force that can be applied of block A so that both the blocks move together is 12N, the maximum force that can be applied on block B for the blocks to move together is?
Please explain properly.
10 months ago

Answers : (3)

Arun
22739 Points
							
When the blocks move together the acceleration will be same.  block A = mass4 kg and If f is the force of friction between A and B
F- f = mb-a  
And f = maa...  
So a = f/ma = 12/4 = 3m/s2
so F-12 = 8*3 = 24
F = 12+24 = 36 N
10 months ago
Kavya Singh
8 Points
							
Answer is given to be 27 newton as in the archive of jee mains from fiitjee.
 This question is asked in jee main 2014.
10 months ago
Arun
22739 Points
							
Dear Kavya
 
I have not got the question in jee mains 2014 paper.
 
Please check and I don't think that 27 N is correct
 
Regards
Arun
 
10 months ago
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