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`        A block of mass 4 kg is placed on another block of mass 5kg and block B rests on a smooth horizontal surface. If the maximum force that can be applied of block A so that both the blocks move together is 12N, the maximum force that can be applied on block B for the blocks to move together is?Please explain properly.`
one year ago

Arun
24739 Points
```							When the blocks move together the acceleration will be same.  block A = mass4 kg and If f is the force of friction between A and BF- f = mb-a  And f = maa...  So a = f/ma = 12/4 = 3m/s2so F-12 = 8*3 = 24F = 12+24 = 36 N
```
one year ago
Kavya Singh
8 Points
```							Answer is given to be 27 newton as in the archive of jee mains from fiitjee. This question is asked in jee main 2014.
```
one year ago
Arun
24739 Points
```							Dear Kavya I have not got the question in jee mains 2014 paper. Please check and I don't think that 27 N is correct RegardsArun
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions