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IIT JEE Entrance Exam

A block of mass 4 kg is placed on another block of mass 5kg and block B rests on a smooth horizontal surface. If the maximum force that can be applied of block A so that both the blocks move together is 12N, the maximum force that can be applied on block B for the blocks to move together is?
Please explain properly.

Kavya Singh

7 Years agoGrade

3 Answers

Arun

7 Years ago

When the blocks move together the acceleration will be same. block A = mass4 kg and If f is the force of friction between A and B

F- f = mb-a

And f = maa...

So a = f/ma = 12/4 = 3m/s2

so F-12 = 8*3 = 24

F = 12+24 = 36 N

Kavya Singh

7 Years ago

Answer is given to be 27 newton as in the archive of jee mains from fiitjee.

This question is asked in jee main 2014.

Arun

7 Years ago

Dear Kavya

I have not got the question in jee mains 2014 paper.

Please check and I don't think that 27 N is correct

Regards

Arun

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