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A ball is projected with initial velocity 25m\s down the incline at an angle of 37 degree from incline, inclined at an angle of 37 degree with horizontal. Take acceleration due to gravity to be 10 m\s^2. What will be the range of the projectileon incline?

2 years ago

Tanmay
45 Points

Formula of Range of Projectile is:
R=Vo2x$Sin[(2\Theta +\beta ) + Sin\beta )/gcos^{2}\beta$
Now Substituting the values:
R=625x[Sin(2x37+37)+Sin37)/10xcos237
=150m
2 years ago
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• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions