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Grade: 12th pass
        
A 10 cm long rod carries a charge of +50microC distributed uniformly along its length. Find the magniutde of electric feild at a point 10 cm from both the ends of the rods.....plz help with this...
4 years ago

Answers : (1)

Yash Arora
41 Points
							
taking one end or rod at origin , assume a charge Dq over it having lenght Dx
 
if charge on rod is Q and lenght is X then Dq = (Q*Dx)/(X)
 
hence field = K ( Dq)/((X+10)^2)  
put Dq and integrate Dx with limit 0 to X 
 
4 years ago
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