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`        60ml of a mixture of Nitrous oxide and nitric oxide was exploded with excess of hydrogen. If 38 ml of N2was formed , calculate the volume of each gas in the mixture.`
3 years ago

```							let x be the volume of NO the reaction takes as 2NO +2H2 ----> N2 +2H2O2x                    xN2O +H2 ----->N2 +H2O60-2x              60-2xthe volume of notrogen collected is 38therefore   60-2x+x=38                x=44hence volume of NO and N2O are 44 and 16 respectively
```
one month ago
```							Dear student If we take the volume of the mixture to be 2x ml of NO. Then we get that the  volume of N2O will be present = (60−2x) ml.We can write the balanced chemical equations as such:Equation-               2NO + 2H2 -> N2+2H2O  .Number of moles -   2x                    x.Equation-                N2O + H2→ N2+H2O.Number of moles-  60−2x         60−2x.Thus from the quetion we get to know that the volume of N2 collected is 38 ml.Hence, we can write that 60−2x+x=38 or x=22 ml.Therefore, the volumes of NO and N2O which are present in the mixture will be:The volume of NO will be=2x=2×22=44 ml.The volume of N2O will be=60−44−16 m.Regards
```
one month ago
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