4 moles of helium are mixed with three moles of hydrogen to form a mixture molar mass of helium is 4g formed and that of hydrogen is 2 gram equivalent degree of freedom of the mixture is

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Arun · Answer

Cv = 3*5R/2 + 4*3R/2 =27R/2 Cp = Cv + R = 27R/2 + R =29R/2 now you can calculate equivalent degree of freedom

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4 moles of helium are mixed with three moles of hydrogen to form a mixture molar mass of helium is 4g formed and that of hydrogen is 2 gram equivalent degree of freedom of the mixture is

4 moles of helium are mixed with three moles of hydrogen to form a mixture molar mass of helium is 4g formed and that of hydrogen is 2 gram equivalent degree of freedom of the mixture is

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4 moles of helium are mixed with three moles of hydrogen to form a mixture molar mass of helium is 4g formed and that of hydrogen is 2 gram equivalent degree of freedom of the mixture is

4 moles of helium are mixed with three moles of hydrogen to form a mixture molar mass of helium is 4g formed and that of hydrogen is 2 gram equivalent degree of freedom of the mixture is

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