Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        3D geometry jee adv 13 ques doubt....pls help me out .....`
2 years ago

Utkarsh
43 Points
```							Any point B on line is (2 – 2, – – 1, 3)Point B lies on the plane for some  (2 – 2) + (– – 1) + 3 = 3 4 = 6  32   B 1, 5 , 92 2      The foot of the perpendicular from point (– 2, – 1, 0) on the plane is the point A (0, 1, 2) D.R. of AB = 1, 7 , 52 2     (2, –7, 5)Hence x y 1 z 22 7 5
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions