+91-87964 74404
FlagBACK
Question icon
Grade 12IIT JEE Entrance Exam

find the answer for the following question a wheel is initially at rest is subjected to an angular acceleration and it completes 10 rotations in time 't', then the time taken by it to complete next 10 rotations

Profile image of RAM SAI CHARAN
16 Years agoGrade 12
Answers icon

1 Answer

Profile image of Vikas TU
6 Years ago
θ = 1/2 a t²
For 10 rotations :
10 × 2π = 1/2 a t²
a = 40 π/t² - - - - - - - - ( i )
As total rotations = 20, with the help of eq i
T² = 80 π/a
=2t²
T = √2 t
After 10 rotations = ( √2 - 1 ) t

Other Related Questions on iit jee entrance exam

question mark

Let S={x:x belongs to R(√3+√2)^(x^2-4) - (√3-√2)^(x^2-4)=10}. Then n(S) is equal to-

iit jee entrance exam
1 Answer Available

Last Activity: 11 Months ago

question mark
My rank is 29k, General, should I opt for any state college cse branch or some Nits in which in which I am getting ECE , chemical, mechanics etc....
 
iit jee entrance exam
1 Answer Available

Last Activity: 3 Years ago

question mark
How is Ranquer Eduzone,comparing, Akash,Fitjee,Resonance,Naryana
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago

question mark
Can class 9th students study syllabus class  of 11th 
iit jee entrance exam
3 Answers Available

Last Activity: 4 Years ago

question mark
Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?
iit jee entrance exam
1 Answer Available

Last Activity: 4 Years ago