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Atomic weight of Boron is 10.81 and it has two isotopes 5B10 and 5B11. Then the ratio 5B10:5B11 in nature would be
(a) 19:81
(b) 10:11
(c) 15: 16
(d) 81: 19
(a)
Suppose that,
The no. of 10B type atoms = x
and the no. of 11B type atoms = y
Weight of 10B type atoms = 10x
Weight of 11B type atoms = 11y
Total no. of atoms = x + y
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