Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g = 10 m/s2)
(a) 30m
(b) 40m
(c) 12m
(d) 20m
(b)
Here u = 72 km/h = 20 m/s; v = 0;
a =- mg = -0.5 × 10 =-5m/s2
As v2 = u1 + 2as,
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !