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Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is (taking g = 10 m/s2)
(a) 30m
(b) 40m
(c) 12m
(d) 20m
(b)
Here u = 72 km/h = 20 m/s; v = 0;
a =- mg = -0.5 × 10 =-5m/s2
As v2 = u1 + 2as,
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