v\\\\:* {behavior:url(#default#VML);}o\\\\:* {behavior:url(#default#VML);}w\\\\:* {behavior:url(#default#VML);}.shape {behavior:url(#default#VML);}Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be(a) 7 sqrt2(b) 5 sqrt2(c) 3 sqrt2(d) sqrt2
Simran Bhatia , 11 Years ago
Grade 11
1 Answers
Hrishant Goswami
Last Activity: 11 Years ago
(a)
Masses of the pieces are 1, 1,3 kg. Hence
(1 × 21)2 + (1 × 21)2 = (3 × V)2
That is, V = 7sqrt2
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