Flag IIT JEE Entrance Exam> velocity-of-heaviest-fragment...
question mark

v\\\\:* {behavior:url(#default#VML);}o\\\\:* {behavior:url(#default#VML);}w\\\\:* {behavior:url(#default#VML);}.shape {behavior:url(#default#VML);}Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be(a) 7 sqrt2(b) 5 sqrt2(c) 3 sqrt2(d) sqrt2

Simran Bhatia , 11 Years ago
Grade 11
anser 1 Answers
Hrishant Goswami

Last Activity: 11 Years ago

(a)

Masses of the pieces are 1, 1,3 kg.  Hence    

(1 × 21)2 + (1 × 21)2 = (3 × V)2

That is, V = 7sqrt2

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...