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A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be (a) 7 sqrt2 (b) 5 sqrt2 (c) 3 sqrt2 ( d) sqrt2



A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be


        (a)    7 sqrt2 


        (b)    5  sqrt2


(c)    3 sqrt2


(d)   sqrt2


Grade:11

1 Answers

Hrishant Goswami
343 Points
7 years ago

(a)

Masses of the pieces are 1, 1,3 kg.  Hence    

(1 × 21)2 + (1 × 21)2 = (3 × V)2

That is, V = 7sqrt2

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