The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by

(a)    2

(b)    1

(c)    0.5

(d)    0.25

Question

The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by

(a) 2

(b) 1

(c) 0.5

(d) 0.25

Aditi Chauhan · Answer

(a)

Magnetic moment = M; Initial angle through which magnet is turned (q₁) = 90° and final angle through which magnet is turned (q₂) = 60°. Work done in turning the magnet, through 90^o(W₁) = MB (cos 0° - cos 90°)

= MB (1-0) = MB.

Similarly, W₂ = MB (cos 0° - cos 60°)

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The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by (a) 2 (b) 1 (c) 0.5 (d) 0.25

The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by

(a)    2

(b)    1

(c)    0.5

(d)    0.25

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The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by (a) 2 (b) 1 (c) 0.5 (d) 0.25

The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by (a) 2 (b) 1 (c) 0.5 (d) 0.25

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The work done in turning a magnet of magnetic moment M by an angle of 90° from the meridian, is n times the corresponding work done to turn it through an angle of 60°. The value of n is given by

(a) 2

(b) 1

(c) 0.5

(d) 0.25