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A bar magnet is oscillating in the earths magnetic field with a period T. What happens to its period of motion, if its mass is quadrupled (a) Motion remains simple harmonic with new period = T/2. (b) Motion remains simple harmonic with new period =2T (c) Motion remains simple harmonic with new period = 4T (d) Motion remains simple harmonic and the period stays nearly constant



A bar magnet is oscillating in the earths magnetic field with a period T. What happens to its period of motion, if its mass is quadrupled


(a)    Motion remains simple harmonic with new period = T/2.


(b)    Motion remains simple harmonic with new period =2T


(c)    Motion remains simple harmonic with new period = 4T


(d)    Motion remains simple harmonic and the period stays nearly constant


Grade:11

2 Answers

Aditi Chauhan
askIITians Faculty 396 Points
7 years ago

(b)

The time period of a bar magnet in a magnetic field is given by.

 

Here, I = moment of inertia proportional m, M = moment of magnet,

B = magnetic field.

so, T becomes twice as mass becomes four times

Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

Usetheformula:T=2π squareroot( I/MB )​
​But: I ∝ m
T′ = 2π squareroot( 4I/MB)​​
⇒ T′/T ​= 2
T′ = 2T

Thanks and Regards

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