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As a result of change in the magnetic flux linked to the closed loop shown in the Fig, an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is (a) QV (b) 2QV (c) QV/2 (d) Zero



As a result of change in the magnetic flux linked to the closed loop shown in the Fig,



        an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is


        (a)    QV


        (b)    2QV


        (c)    QV/2


(d)    Zero


Grade:10

1 Answers

Vikas TU
14149 Points
3 years ago
Work done in taking a charge = Q (Given)
Volt induced in the loop = V (Given)
Work done in moving a test charge is equal to Q around a loop that has an induced emf ∈ making it Q∈.Therefore, as the induced electric field due to change in magnetic field is non-conservative the work done due to a charge will become W = QV
Hence, The work done (in joule) in taking a charge Q coulomb once along the loop is QV

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