As a result of change in the magnetic flux linked to the closed loop shown in the Fig,an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is(a) QV(b) 2QV(c) QV/2(d) Zero

Work done in taking a charge = Q (Given)

Volt induced in the loop = V (Given)

Work done in moving a test charge is equal to Q around a loop that has an induced emf ∈ making it Q∈.Therefore, as the induced electric field due to change in magnetic field is non-conservative the work done due to a charge will become W = QV

Hence, The work done (in joule) in taking a charge Q coulomb once along the loop is QV