coulomb-once-along-the-loop

Question

Normal 0 false false false false EN-US X-NONE X-NONE As a result of change in the magnetic flux linked to the closed loop shown in the Fig, an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is (a) QV (b) 2QV (c) QV/2 (d) Zero

Vikas TU · Accepted Answer

Work done in taking a charge = Q (Given)Volt induced in the loop = V (Given)Work done in moving a test charge is equal to Q around a loop that has an induced emf ∈ making it Q∈.Therefore, as the induced electric field due to change in magnetic field is non-conservative the work done due to a charge will become W = QVHence, The work done (in joule) in taking a charge Q coulomb once along the loop is QV

IIT JEE Entrance Exam> coulomb-once-along-the-loop...

As a result of change in the magnetic flux linked to the closed loop shown in the Fig,

an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is

(a) QV

(b) 2QV

(c) QV/2

(d) Zero

Navjyot Kalra , 11 Years ago

Vikas TU

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IIT JEE Entrance Exam> coulomb-once-along-the-loop...

As a result of change in the magnetic flux linked to the closed loop shown in the Fig, an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is (a) QV (b) 2QV (c) QV/2 (d) Zero

Navjyot Kalra , 11 Years ago

Vikas TU

Provide a better Answer & Earn Cool Goodies

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Ask a Doubt

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Sum of series 2[n/2] ! [n/2]!/ n! [2Co-2C2+3C2....+[-1]^n[n+1]2Cn] where n is an even positive integer. Kindly provide solution of this question and how to generalise this. How do we know that which expansion will give this?

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I m foreigner,How much mark i need to get into IIT??

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As a result of change in the magnetic flux linked to the closed loop shown in the Fig,

an e.m.f. V volt is induced in the loop. The work done (joules) in taking a charge Q coulomb once along the loop is

(a) QV

(b) 2QV

(c) QV/2

(d) Zero