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The current in self inductance L = 40 mH is to be increased uniformly from 1 amp to 11 amp in 4 milliseconds. The e.m.f. induced in the inductor during the process is
(a) 100 volt
(b) 0.4 volt
(c) 4.0 volt
(d) 440 volt
(a)
Given that L = 40 × 10-3 H,
di = 11 A – 1 A = 10 A and dt = 4 × 10-3 s
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