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Power dissipated across the 80 resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 30 resistor is
(a) 1.0
(b) 0.5
(c) 3.0
(d) 2.0
(c)
Power = V. I = 12R
Potential over 80 = Ri2 = 8 ×0.5 = 4V
This is the potential over parallel branch.
So,
Power of 3W = i1\2R = 1 × 1 × 3 = 3W
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