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Grade upto college level IIT JEE Entrance Exam

Power dissipated across the 80 resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 30 resistor is

width=432

(a) 1.0

(b) 0.5

(c) 3.0

(d) 2.0

Profile image of Amit Saxena
12 Years agoGrade upto college level
Answers icon

1 Answer

Profile image of Aditi Chauhan
12 Years ago

(c)

Power = V. I = 12R

 

Potential over 80 = Ri2 = 8 ×0.5  = 4V

This is the potential over parallel branch.

So,

        Power of 3W = i1\2R = 1 × 1 × 3 = 3W

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