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Grade 11IIT JEE Entrance Exam

If nearly 105 coulombs liberate 1 gm-equivalent of aluminium, then the amount of aluminium (equivalent weight 9), deposited through electrolysis in 20 minutes by a current of 50 amp. will be

(a) 0.6 gm

(b) 0.09 gm

(c) 5.4 gm

(d) 10.8 gm

Profile image of Simran Bhatia
12 Years agoGrade 11
Answers icon

1 Answer

Profile image of Hrishant Goswami
12 Years ago

(c)

m = Zit, 9 = Z × 105, Z = 9 × 10-5

Again,

m = Zit = 9 × 10-5 × 50 × 20 × 60 = 5.4 gm

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