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A heating coil is labelled 100 W, 220 V. The coil is cut in half and the two pieces are joined in parallel to the same source. The energy now liberated per second is (a) 25 J (b) 50 J (c) 200 J (d) 400 J



A heating coil is labelled 100 W, 220 V. The coil is cut in half and the two pieces are joined in parallel to the same source. The energy now liberated per second is


        (a)    25 J


(b)    50 J


        (c)    200 J


        (d)    400 J


 

Grade:11

2 Answers

Hrishant Goswami
343 Points
8 years ago

(d)

Power of heating coil = 100 Wand voltage (V) = 220 volts. When the heating coil is cut into two equal parts and these parts are joined in parallel, then the resistance of the coil is reduced to one-fourth of the previous value. Therefore energy liberated per second becomes 4 times i.e., 4 × 100 = 400 J.

Aditi
13 Points
3 years ago
The coil is cut into half, so the resistance becomes half. Further they both are connected to the same source. Resistance becomes 1/4 and P is inversely proportional to R Pawer becomes 4 times4×100=400

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