A 4 uF capacitor is charged to 400 volts and then its plates are joined through a resistance of 1 kW. The heat produced in the resistance is

(a) 0.16 J

(b) 1.28 J

(b) 0.641

(d) 0.32 J

(d)

The energy stored in the capacitor

   This energy will be converted into heat in the resistor.

Dear Student,
Please find below the solution to your problem.

The energy stored in the capacitor
= 0.5CV^2
= 0.5*4*10^-4*(400)^2
= 0.32 J
This energy will be converted into heat in the resistor.

Thanks and Regards