Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}An astronomical telescope has a length of 44 cm and tenfold magnification. The focal length of the objective lens is(a) 4 cm(b) 40 cm(c) 44 cm(d) 440 cm
Kevin Nash , 11 Years ago
Grade upto college level
1 Answers
Aditi Chauhan
Last Activity: 11 Years ago
(b)
Given: Length of astronomical telescope (f0 + fe) = 44 cm and magnification
(f_0/f_e )=10.
From the given magnification, we find that f0 = 10 fe.
Therefore, 10 fe + fe = 44 or 11 fe = 44 or fe = 4.
And focal length of the objective (f0) = 44 - fe = 44 - 4 = 40 cm.
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