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A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of right is (a) √(A_1 A_2 ) (b) (A_1+A_2)/2 (c) (A_1-A_2)/2 (d) 1/A_1 +1/A_2

A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of right is
    (a)    √(A_1  A_2 )
    (b)    (A_1+A_2)/2
    (c)     (A_1-A_2)/2
    (d)    1/A_1 +1/A_2

Grade:10

3 Answers

Navjyot Kalra
askIITians Faculty 654 Points
8 years ago

(a)
Size of images = A1 and A2. From the displacement method, the area of the source of light = √(A_1 A_2 ).

Shaurya Luthra
9 Points
4 years ago
Can you please elaborate the above answer I am unable to understand. What is the displacement method , how can area be root o& A1A2
 
 
Priyamavi
15 Points
3 years ago
What is displacement method plz explain it elaborate it. How this possible plz help me .I am totally mad in this question 
 

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