IIT JEE Entrance Exam> -area-of-the-source-of-right...

A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of right is
(a) √(A_1 A_2 )
(b) (A_1+A_2)/2
(c) (A_1-A_2)/2
(d) 1/A_1 +1/A_2

Hrishant Goswami , 12 Years ago

Grade 10

3 Answers

Navjyot Kalra

(a)
Size of images = A1 and A2. From the displacement method, the area of the source of light = √(A_1 A_2 ).

Last Activity: 12 Years ago

Shaurya Luthra

Can you please elaborate the above answer I am unable to understand. What is the displacement method , how can area be root o& A1A2

Last Activity: 8 Years ago

Priyamavi

What is displacement method plz explain it elaborate it. How this possible plz help me .I am totally mad in this question

Last Activity: 7 Years ago

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IIT JEE Entrance Exam> -area-of-the-source-of-right...

A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of right is (a) √(A_1 A_2 ) (b) (A_1+A_2)/2 (c) (A_1-A_2)/2 (d) 1/A_1 +1/A_2

Hrishant Goswami , 12 Years ago

Navjyot Kalra

Shaurya Luthra

Priyamavi

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A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall for its two different positions. The area of the source of right is
(a) √(A_1 A_2 )
(b) (A_1+A_2)/2
(c) (A_1-A_2)/2
(d) 1/A_1 +1/A_2