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A ray is incident at an angle of incidence i on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of prism is m, the angle of incidence i is nearly equal to(a) A/u(b) A/2u(c) u A(d)uA/2

Hrishant Goswami , 11 Years ago
Grade 10
anser 3 Answers
Amit Saxena

Last Activity: 11 Years ago

(c)

As refracted ray emerges normally from oppostite surface,

r2 = 0  

        As A = r1 + r2

        .''.     r1 = A

Now, u= sini1/sinr

= i1/r1

=uA

Divyansh Nema

Last Activity: 6 Years ago

        FOR  PRISM ,
 
        A = R1 + R2 
        As the ray emerges normally,
       
       E = 90 DEGREE  .  R2 = 90 
       R1  NEEDS TO BE 0 DEGREE 
     
      A = R2 
      
      U = SIN i/ SIN r 
      
      For small angles ,
      SIN X  =  X  
 
      U  =  SIN i / SIN r 
      U  =  i / r
      U  =  i / A 
      
 
    THUS::::
     
    UA = I

Yash Chourasiya

Last Activity: 4 Years ago

Dear Student

Please see the solution in the attachment.


643-2246_Untitled.png

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

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