Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A ray is incident at an angle of incidence i on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of prism is m , the angle of incidence i is nearly equal to (a) A/u (b) A/2u (c) u A (d) uA/2



A ray is incident at an angle of incidence i on one surface of a prism of small angle A and emerges normally from the opposite surface. If the refractive index of the material of prism is m, the angle of incidence i is nearly equal to


        (a)    A/u


        (b)    A/2u


        (c)    u A


(d)    uA/2


Grade:10

3 Answers

Amit Saxena
35 Points
7 years ago

(c)

As refracted ray emerges normally from oppostite surface,

r2 = 0  

        As A = r1 + r2

        .''.     r1 = A

Now, u= sini1/sinr

= i1/r1

=uA

Divyansh Nema
17 Points
2 years ago
        FOR  PRISM ,
 
        A = R1 + R2 
        As the ray emerges normally,
       
       E = 90 DEGREE  .  R2 = 90 
       R1  NEEDS TO BE 0 DEGREE 
     
      A = R2 
      
      U = SIN i/ SIN r 
      
      For small angles ,
      SIN X  =  X  
 
      U  =  SIN i / SIN r 
      U  =  i / r
      U  =  i / A 
      
 
    THUS::::
     
    UA = I
Yash Chourasiya
askIITians Faculty 256 Points
9 months ago
Dear Student

Please see the solution in the attachment.


643-2246_Untitled.png

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free