HETAV PATEL

Grade 11,

0^pi [x^2.sin2x.sin(pi/2.cosx)]/2x-pi

0^pi [x^2.sin2x.sin(pi/2.cosx)]/2x-pi

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1 Answers

Vikas TU
14149 Points
3 years ago
Dear student 
Question is not clear 
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Good Luck
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