Question icon
Grade 10IIT JEE Entrance Exam

Two bodies, A (of mass 1 kg) and B (of mass 3 kg), are dropped from heights of 16m and 25m, respectively. The ratio of the time taken by them to reach the ground is

(a) 12/5

(b) 5/12

(c) 4/5

(d) 5/4

Profile image of Aditi Chauhan
12 Years agoGrade 10
Answers icon

2 Answers

Profile image of Jitender Pal
12 Years ago

(c)
Let t1 & t2 be time taken to reach the ground then from the formula,
h=   1/2 gt^2,
For first body,   16  =1/2   gt_(1 )^(   2)
For second body,   25 =1/2   gt_2^(   2)
 16/25  =(t_1^(  2))/(t_2^(  2) )   ?  t_1/t_2   =  4/5.

Profile image of Adarsh
8 Years ago
We know v=u+ at ,as it falls downward a=g and u =0V=gt^2g=v/(t^2)For height 16m16/(t1^2)=g -equation 1For height 25m25/(t2^2)=g -equation 2From equation 1 and 2 16/(t1^2)=25/(t2^2)t1/t2=√(16÷25)t1/t2=4/5☺