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question mark

A car moving with a speed of 40 km/h can be stopped by applying brakes at least after 2m. If the same car is moving with a speed of 80 km/h, what is the minimum stopping distance?
(a)8m
(b)6m
(c)4m
(d)2m

Aditi Chauhan , 12 Years ago
Grade 10
anser 4 Answers
Jitender Pal

(a)
If F is retarding force and s the stopping distance then
    1/2  m2   =Fs
    For same retarding force, s a v2
        s_2/s_1 = (v_2/v_1 )^2  =((80 km/h)/(40 km/h))^2  =4    
       s2 = 4s1 = 4 × 2 = 8m

Last Activity: 12 Years ago
vivek sharma
F is retarding force, and x is stopping distance. Then F. x = 1/2 mv² F. 2 =1/2m(40)² F=1/4.m.1600 X’ = mv²/2F X’ = 6400m/1600m = 8 metre
Last Activity: 8 Years ago
Nazir Hossain
First calculate the acceration in first case v ^2= 2aSa=v^2/2s , a= 1600/2*2, a=400m/s^2Now, calculate distance in 2nd caseS= v^2/2a , S= 6400/2*400, S= 8 m
Last Activity: 8 Years ago
ammalu
we known that v2=u2+2as then a=u2/2s =(50* 5/ 18)2 /2*6
s=u2/2a then (100*5/18)2        =24
                 2 * (50*5/ 18)2
                          12
Last Activity: 7 Years ago
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