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If a car at rest accelerates uniformly to a speed of 144 km/h in 20 s, it covers a distance of
(a) 2880m
(b) 1440m
(c) 400m
(d) 20m
(c)Initial velocity of car (u) = 0 Final velocity of car (v) = 144 Km/hr = 40 m/s Time taken = 20 s We know that, v = u + at 40 = a × 20 => a = 2 m/s? Also, v2 - u2 = 2as s=(v^2 –u^2)/2a s=((40)^2- (0)^2)/(2×2)= 1600/4=400 m.
(c)
Initial velocity of car (u) = 0
Final velocity of car (v) = 144 Km/hr
= 40 m/s
Time taken = 20 s
We know that, v = u + at
40 = a × 20 Þ a = 2 m/s?
Also, v2 - u2 = 2as
Þ
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