Flag IIT JEE Entrance Exam> average-impulse-imparted-to-the-bullet...
question mark

A bullet is fired from a gun. The force on the bullet is given by

F = 600 - 2 × 105 t

Where, F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?

(a) 1.8 N-s

(b) Zero

(c) 9 N-s

(d) 0.9 N-s

Kevin Nash , 12 Years ago
Grade upto college level
anser 1 Answers
Simran Bhatia

(d)
Given F = 600-(2 × 105t)
The force is zero at time t, given by.
0 = 600 - 2 × 105 t
? t =  600/(2×?10?^5 )=3×?10?^(-3)  second
? Impulse = ∫_0^t¦? Fdt  = ∫_0^(3×?10?^(-3))¦? (600 -2×?10?^5 t)  dt??
= [600 t -(2×?10?^5 t^2)/2]^(3×?10?^(-3) )
= 600×3×?10?^(-3)- ?10?^5 (3×?10?^(-3) )^2
=1.8-0.9 =0.9 Ns

Last Activity: 12 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments