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A bullet is fired from a gun. The force on the bullet is given by
F = 600 - 2 × 105 t
Where, F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel. What is the average impulse imparted to the bullet?
(a) 1.8 N-s
(b) Zero
(c) 9 N-s
(d) 0.9 N-s
(d)Given F = 600-(2 × 105t) The force is zero at time t, given by. 0 = 600 - 2 × 105 t ? t = 600/(2×?10?^5 )=3×?10?^(-3) second ? Impulse = ∫_0^t¦? Fdt = ∫_0^(3×?10?^(-3))¦? (600 -2×?10?^5 t) dt??= [600 t -(2×?10?^5 t^2)/2]^(3×?10?^(-3) ) = 600×3×?10?^(-3)- ?10?^5 (3×?10?^(-3) )^2 =1.8-0.9 =0.9 Ns
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