Flag IIT JEE Entrance Exam> rocket-is-set-for-vertical-firing...
question mark

Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A 5000 kg rocket is set for vertical firing. The exhaust speed is 800 m/s. To give an initial upward acceleration of 20 m/s2, the amount of gas ejected per second to supply the needed thrust will be (Take g = 10 m/s2)(a) 127.5kg/s(b) 137.5kg/s(c) 155.5 kg/s(d) 187.5 kg/s

Kevin Nash , 11 Years ago
Grade upto college level
anser 5 Answers
Simran Bhatia

Last Activity: 11 Years ago

(d)

Given: Mass of rocket (m) = 5000 Kg Exhaust speed (v) = 800 m/s Acceleration of rocket (a) = 20 m/s2

Gravitational acceleration (g) = 10 m/s2

We know that upward force

F = m (g + a) = 5000 (10 + 20)  

= 5000 × 30 = 150000 N.

We also know that amount of gas ejected

 

Aswin M

Last Activity: 6 Years ago

Mass of rocket(M)= 5000 kg
Exhaust speed(v)=800m/s^2
Acceleration(a)=20m/s^2
acceleration due to gravity (g)=10 m/s^2
F=m(g+a)=5000(10+20)=15000N
amount of gas ejected per second= F/v=15000/800=187.5 kg/s
Thank you!!!

Aayan Ta

Last Activity: 5 Years ago

:GivenMass of rocket(m)= 5000 kgExhaust speed(v)=800m/s^2   :FormulaAcceleration(a)=20m/s^2​v(dm/dt)=m(a+g)

Solution
800(dm/dt)=5000(20+10
dm/dt= 187.5kg/s

Sivaneeth R

Last Activity: 5 Years ago

We know that F=m(g+a)
=5000(10+20)
=5000×30
=150000N
 
Amount of gas ejected per second=F/V
150000/800
=187.5kg/s
=150000/800
 

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below in the attached image solution to your problem.

Thanks and Regards
645-772_01.PNG

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...