Normal 0false false falseEN-US X-NONE X-NONE/* Style Definitions */table.MsoNormalTable{mso-style-name:Table Normal;mso-tstyle-rowband-size:0;mso-tstyle-colband-size:0;mso-style-noshow:yes;mso-style-priority:99;mso-style-parent:;mso-padding-alt:0in 5.4pt 0in 5.4pt;mso-para-margin-top:0in;mso-para-margin-right:0in;mso-para-margin-bottom:10.0pt;mso-para-margin-left:0in;line-height:115%;mso-pagination:widow-orphan;font-size:11.0pt;font-family:Calibri,sans-serif;mso-ascii-font-family:Calibri;mso-ascii-theme-font:minor-latin;mso-hansi-font-family:Calibri;mso-hansi-theme-font:minor-latin;mso-bidi-font-family:Times New Roman;mso-bidi-theme-font:minor-bidi;}A 5000 kg rocket is set for vertical firing. The exhaust speed is 800 m/s. To give an initial upward acceleration of 20 m/s2, the amount of gas ejected per second to supply the needed thrust will be (Take g = 10 m/s2)(a) 127.5kg/s(b) 137.5kg/s(c) 155.5 kg/s(d) 187.5 kg/s
Kevin Nash , 11 Years ago
Grade upto college level
5 Answers
Simran Bhatia
Last Activity: 11 Years ago
(d)
Given: Mass of rocket (m) = 5000 Kg Exhaust speed (v) = 800 m/s Acceleration of rocket (a) = 20 m/s2
Gravitational acceleration (g) = 10 m/s2
We know that upward force
F = m (g + a) = 5000 (10 + 20)
= 5000 × 30 = 150000 N.
We also know that amount of gas ejected
Aswin M
Last Activity: 6 Years ago
Mass of rocket(M)= 5000 kg
Exhaust speed(v)=800m/s^2
Acceleration(a)=20m/s^2
acceleration due to gravity (g)=10 m/s^2
F=m(g+a)=5000(10+20)=15000N
amount of gas ejected per second= F/v=15000/800=187.5 kg/s
Thank you!!!
Aayan Ta
Last Activity: 5 Years ago
:GivenMass of rocket(m)= 5000 kgExhaust speed(v)=800m/s^2 :FormulaAcceleration(a)=20m/s^2v(dm/dt)=m(a+g)
Solution:
800(dm/dt)=5000(20+10
dm/dt= 187.5kg/s
Sivaneeth R
Last Activity: 5 Years ago
We know that F=m(g+a)
=5000(10+20)
=5000×30
=150000N
Amount of gas ejected per second=F/V
150000/800
=187.5kg/s
=150000/800
Rishi Sharma
Last Activity: 4 Years ago
Dear Student, Please find below in the attached image solution to your problem.
Thanks and Regards
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