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Grade 11IIT JEE Entrance Exam

A particle of mass m is moving with a uniform velocity v1. It is given an impulse such that its velocity becomes v2. The impulse is (equal to

(a) m [|v2| = |v1|

(b) m[v22 - v=12]

(c) m[v1 + v2]

(d) [v2 – v1]

Profile image of Simran Bhatia
12 Years agoGrade 11
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1 Answer

Profile image of Navjyot Kalra
12 Years ago

(d)

Impulse = final momentum - initial momentum = m(v2-v1)

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