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A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be (a) 7√2 (b) 5√2 (c) 3√2 (d) √2
(a)Masses of the pieces are 1, 1,3 kg. Hence (1 × 21)2 + (1 × 21)2 = (3 × V)2 That is, V = 7 √2.
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