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A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be(a) 7√2(b) 5√2(c) 3√2(d) √2

Simran Bhatia , 11 Years ago
Grade 11
anser 1 Answers
Navjyot Kalra

Last Activity: 11 Years ago

(a)
Masses of the pieces are 1, 1,3 kg.  Hence   
(1 × 21)2 + (1 × 21)2 = (3 × V)2
That is, V = 7 √2.

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