Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be (a) 7√2 (b) 5√2 (c) 3√2 (d) √2

A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1: 1: 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of heaviest fragment in m/s will be
    (a)    7√2 
    (b)    5√2
     (c)    3√2
     (d)    √2

Grade:11

1 Answers

Navjyot Kalra
askIITians Faculty 654 Points
7 years ago

(a)
Masses of the pieces are 1, 1,3 kg.  Hence   
(1 × 21)2 + (1 × 21)2 = (3 × V)2
That is, V = 7 √2.

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free