Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
This section contains 5 questions. The answer to each of the questions is a single digit integer ranging from 0 to 9.
While measuring length of an object it was observed that the zero of the vernier lies between 1.4 and 1.5 of the main scale and the fifth vernier division coincides with a main scale division. If the length of the object measured is l, the value of (l – 1.4) in terms of the least count C of the instrument is yC. Find y.
5
Let x = – 1.4
Then 1.4 + x + 5V = 1.4 + 5 S, where S denotes the length of one main scale division, and V denotes the length of one vernier scale division.
Hence, x = 5 S – 5 V = (1S – 1V) = 5C
\ y = 5
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !