Flag IIT JEE Entrance Exam> circles...
question mark

Find equation of circle having centre in first quadrant, touching x axis, having common tangent y=sqrt(3)x +4with circle x^2 + y^2 + 4x + 4y + 4 = 0 such that distance b/w two circles along x axis is 3 units.

Alisha Kapoor , 11 Years ago
Grade 12
anser 2 Answers
Arun

Last Activity: 4 Years ago

Dear student,
 
Your question is wrong.We haveC:x2+y2+4x+4y+4=0Centre is (−2,2) and radius is (−2)2+(−2)2−4−−−−−−−−−−−−−−−√=4+4−4−−−−−−−√=2If y=3√x+4 touches C then perpendicular from centre to line must beequal to radius of circle.y=3√x+4 ⇒3√x−y+4=0Length of perpendicular=∣∣3√×(−2)−2+4∣∣(3√)2+(−1)2√=∣∣23√+2∣∣2=2(3√+1)2=3√+1 which is not equal to radius of cirlcle. Hence line cannot be tangentto cirlce.Hence information given in question is incorrect.

Vikas TU

Last Activity: 4 Years ago

Dear student 
Question is not clear 
Please upload an image.
We will happy to help you.
Good luck 
Cheers 

Provide a better Answer & Earn Cool Goodies

Enter text here...
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments


Ask a Doubt

Get your questions answered by the expert for free

Enter text here...