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A proton is accelerated through a potential difference of 1V. Its kinetic energy is a) 1 eV b) Zero c) 2 eV d) 4 eV

 A proton is accelerated through a potential difference of 1V. Its kinetic energy is


a)      1 eV


b)      Zero


c)      2 eV


 


d)      4 eV

Grade:11

2 Answers

Arun
25750 Points
3 years ago
If a proton is accelerated from rest through a potential difference of 30 kV, it is given an energy of 30 keV (30,000 eV) and it can break up as many as 6000 of these molecules (30,000 eV ÷ 5 eV per molecule= 6000 molecules).
Vikas TU
14149 Points
3 years ago
PE = qV where q =1.6 x 10^-19 C and V = 1000 V 
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then: 
PE* = 0, KE* = 1/(2mv^2)
Now since PE +KE = Total energy =PE* + KE*
qV + 0 = 0 + 1/2mv^2 
Or: KE = qV = 1.6 10^-15 J  

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