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A proton is accelerated through a potential difference of 1V. Its kinetic energy is

a) 1 eV

b) Zero

c) 2 eV

d) 4 eV

Radhika Batra , 12 Years ago
Grade 11
anser 2 Answers
Arun
If a proton is accelerated from rest through a potential difference of 30 kV, it is given an energy of 30 keV (30,000 eV) and it can break up as many as 6000 of these molecules (30,000 eV ÷ 5 eV per molecule= 6000 molecules).
Last Activity: 5 Years ago
Vikas TU
PE = qV where q =1.6 x 10^-19 C and V = 1000 V 
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then: 
PE* = 0, KE* = 1/(2mv^2)
Now since PE +KE = Total energy =PE* + KE*
qV + 0 = 0 + 1/2mv^2 
Or: KE = qV = 1.6 10^-15 J  
Last Activity: 5 Years ago
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