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A proton is accelerated through a potential difference of 1V. Its kinetic energy isa) 1 eVb) Zeroc) 2 eVd) 4 eV

Radhika Batra , 11 Years ago
Grade 11
anser 2 Answers
Arun

Last Activity: 4 Years ago

If a proton is accelerated from rest through a potential difference of 30 kV, it is given an energy of 30 keV (30,000 eV) and it can break up as many as 6000 of these molecules (30,000 eV ÷ 5 eV per molecule= 6000 molecules).

Vikas TU

Last Activity: 4 Years ago

PE = qV where q =1.6 x 10^-19 C and V = 1000 V 
Assuming the proton no longer experiences the potential energy and it is all converted to kinetic energy then: 
PE* = 0, KE* = 1/(2mv^2)
Now since PE +KE = Total energy =PE* + KE*
qV + 0 = 0 + 1/2mv^2 
Or: KE = qV = 1.6 10^-15 J  

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