Assuming the given motion takes place in Horizontal plane.

 

Steps:

1) The bead will start sliding when centripetal force is equal to limiting friction.

i. e.

mw^2L = f(max)

=> mw^2 L= u N ----(1)

 

2) We know that,

Here. Normal Reaction is provided by Tangential force.

F(t) = mLα =N ---(2)

 

3 ) Substituting value of N in eq. (1),

Now,

At time t,.

w = 0 + αt

w = αt

 

Now,

mw^2L = umLα

=> m(αt) ^2 L = umLα

=> αt^2 = u

=> t =√(u/α) .

 

At time t , bead will start sliding.

When we are giving an angular acceleration to the rod, the bead is also having an instantaneous. acceleration a=La. This will happen when a force is exerted on the bead by the rod. The bead has a tendency to move away from the centre. But due to the friction between the bead and the rod, this does not happen to the extent to which frictional force is capable of holding the bead. The frictional force here provides the necessary centripetal force. If instantaneous angular velocity is o then