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1) An astronomical telescope has an angular magnification of magnitude 5 for distant objects. The separation between the objective and the eyepiece is 36 cm and the final image is formed at infinity. The focal length f0 of the objective and the length fe of the eyepiece are

a) fo = 45 cm and fe = -9 cm

b) fo = 50 cm and fe = 10 cm

c) fo = 7.2 cm and fe = 5cm

d) fo = 30 cm and fe = 6 cm

Radhika Batra , 12 Years ago
Grade 11
anser 1 Answers
Vikas TU
m = - fo / fe
fo = 5 fe
L = fo + fe
fe = 36/6 = 6 cm
fo = 30 cm
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Last Activity: 5 Years ago
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