1)Force F is given in terms of time t and distance ‘x’ by F = A sin Ct + B cosdx. Then dimensions of A/B and C/D are(a) [M0L0T0], [M0L0T–1](b) [MLT–2], [M0L–1T0](c) [M0L0T0], [M0LT-1](d) [M0L–1T-1], [M0L0T0]

F=A cos Bx+C sin Dt

It is a common saying in mathematics that the elements inside cos and sin function is always constant.

So here in the above equation

B x. & Dt must be dimensionless

Since x=[L] &t=[T]

So B=[L]^-1 & D=[T]^-1

So,D/B=[LT^-1]

Thanks